Base | Representation |
---|---|
bin | 11010010001010011001101… |
… | …001101110100100011011011 |
3 | 120011002022221021112021110111 |
4 | 122101103031031310203123 |
5 | 110120433423140333221 |
6 | 1045421241542225151 |
7 | 33223230625244206 |
oct | 3221231515644333 |
9 | 504068837467414 |
10 | 115538063214811 |
11 | 338a5465682876 |
12 | 10b600737251b7 |
13 | 4c612672229b3 |
14 | 2076101b9693d |
15 | d556244c6be1 |
hex | 6914cd3748db |
115538063214811 has 2 divisors, whose sum is σ = 115538063214812. Its totient is φ = 115538063214810.
The previous prime is 115538063214797. The next prime is 115538063214857. The reversal of 115538063214811 is 118412360835511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115538063214811 - 27 = 115538063214683 is a prime.
It is not a weakly prime, because it can be changed into another prime (115538063214881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57769031607405 + 57769031607406.
It is an arithmetic number, because the mean of its divisors is an integer number (57769031607406).
Almost surely, 2115538063214811 is an apocalyptic number.
115538063214811 is a deficient number, since it is larger than the sum of its proper divisors (1).
115538063214811 is an equidigital number, since it uses as much as digits as its factorization.
115538063214811 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 49.
The spelling of 115538063214811 in words is "one hundred fifteen trillion, five hundred thirty-eight billion, sixty-three million, two hundred fourteen thousand, eight hundred eleven".
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