Base | Representation |
---|---|
bin | 10000110100000101000… |
… | …000110111000111000011 |
3 | 11002110100220222111100110 |
4 | 100310011000313013003 |
5 | 122412310130030220 |
6 | 2242444121322403 |
7 | 146322432424545 |
oct | 20640500670703 |
9 | 4073326874313 |
10 | 1155430314435 |
11 | 406019321711 |
12 | 167b1b336403 |
13 | 84c588a02b7 |
14 | 3dccd0b1695 |
15 | 200c6e4cbe0 |
hex | 10d050371c3 |
1155430314435 has 16 divisors (see below), whose sum is σ = 1848973906080. Its totient is φ = 616134366720.
The previous prime is 1155430314419. The next prime is 1155430314439. The reversal of 1155430314435 is 5344130345511.
It is not a de Polignac number, because 1155430314435 - 24 = 1155430314419 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1155430314393 and 1155430314402.
It is not an unprimeable number, because it can be changed into a prime (1155430314439) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5845440 + ... + 6039869.
It is an arithmetic number, because the mean of its divisors is an integer number (115560869130).
Almost surely, 21155430314435 is an apocalyptic number.
1155430314435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1155430314435 is a deficient number, since it is larger than the sum of its proper divisors (693543591645).
1155430314435 is a wasteful number, since it uses less digits than its factorization.
1155430314435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11891798.
The product of its (nonzero) digits is 216000, while the sum is 39.
Adding to 1155430314435 its reverse (5344130345511), we get a palindrome (6499560659946).
The spelling of 1155430314435 in words is "one trillion, one hundred fifty-five billion, four hundred thirty million, three hundred fourteen thousand, four hundred thirty-five".
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