Base | Representation |
---|---|
bin | 11010010001011000010001… |
… | …111000001101000010001001 |
3 | 120011002211222212212220101202 |
4 | 122101120101320031002021 |
5 | 110121031102044034423 |
6 | 1045423542240553545 |
7 | 33223512615335513 |
oct | 3221302170150211 |
9 | 504084885786352 |
10 | 115543510143113 |
11 | 338a7800298708 |
12 | 10b611339228b5 |
13 | 4c619248440b0 |
14 | 207649b356bb3 |
15 | d558427b1728 |
hex | 691611e0d089 |
115543510143113 has 32 divisors (see below), whose sum is σ = 124832378361600. Its totient is φ = 106312629113856.
The previous prime is 115543510143011. The next prime is 115543510143167. The reversal of 115543510143113 is 311341015345511.
It is a cyclic number.
It is not a de Polignac number, because 115543510143113 - 224 = 115543493365897 is a prime.
It is not an unprimeable number, because it can be changed into a prime (115543510142113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 16461530918 + ... + 16461537936.
It is an arithmetic number, because the mean of its divisors is an integer number (3901011823800).
Almost surely, 2115543510143113 is an apocalyptic number.
115543510143113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
115543510143113 is a deficient number, since it is larger than the sum of its proper divisors (9288868218487).
115543510143113 is a wasteful number, since it uses less digits than its factorization.
115543510143113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10721.
The product of its (nonzero) digits is 54000, while the sum is 38.
Adding to 115543510143113 its reverse (311341015345511), we get a palindrome (426884525488624).
The spelling of 115543510143113 in words is "one hundred fifteen trillion, five hundred forty-three billion, five hundred ten million, one hundred forty-three thousand, one hundred thirteen".
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