Base | Representation |
---|---|
bin | 10000110100001100110… |
… | …000110000110100010011 |
3 | 11002110200222121001121011 |
4 | 100310030300300310103 |
5 | 122413041414441313 |
6 | 2242505043511351 |
7 | 146325601405462 |
oct | 20641460606423 |
9 | 4073628531534 |
10 | 1155560312083 |
11 | 406085741891 |
12 | 167b56988557 |
13 | 84c797b7998 |
14 | 3dd024709d9 |
15 | 200d357a93d |
hex | 10d0cc30d13 |
1155560312083 has 2 divisors, whose sum is σ = 1155560312084. Its totient is φ = 1155560312082.
The previous prime is 1155560311987. The next prime is 1155560312099. The reversal of 1155560312083 is 3802130655511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1155560312083 is a prime.
It is a super-2 number, since 2×11555603120832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1155560312183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 577780156041 + 577780156042.
It is an arithmetic number, because the mean of its divisors is an integer number (577780156042).
Almost surely, 21155560312083 is an apocalyptic number.
1155560312083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1155560312083 is an equidigital number, since it uses as much as digits as its factorization.
1155560312083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 40.
Adding to 1155560312083 its reverse (3802130655511), we get a palindrome (4957690967594).
The spelling of 1155560312083 in words is "one trillion, one hundred fifty-five billion, five hundred sixty million, three hundred twelve thousand, eighty-three".
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