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115625541481 is a prime number
BaseRepresentation
bin110101110101111010…
…0011011111101101001
3102001110010212002112021
41223223310123331221
53343300114311411
6125041224344441
711232210613012
oct1535364337551
9361403762467
10115625541481
114504467074a
121a4aa915121
13ab98b27b88
14584c39a009
15301ae14a71
hex1aebd1bf69

115625541481 has 2 divisors, whose sum is σ = 115625541482. Its totient is φ = 115625541480.

The previous prime is 115625541431. The next prime is 115625541539. The reversal of 115625541481 is 184145526511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115589120256 + 36421225 = 339984^2 + 6035^2 .

It is an emirp because it is prime and its reverse (184145526511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115625541481 is a prime.

It is a super-2 number, since 2×1156255414812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115625541431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57812770740 + 57812770741.

It is an arithmetic number, because the mean of its divisors is an integer number (57812770741).

Almost surely, 2115625541481 is an apocalyptic number.

It is an amenable number.

115625541481 is a deficient number, since it is larger than the sum of its proper divisors (1).

115625541481 is an equidigital number, since it uses as much as digits as its factorization.

115625541481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 192000, while the sum is 43.

The spelling of 115625541481 in words is "one hundred fifteen billion, six hundred twenty-five million, five hundred forty-one thousand, four hundred eighty-one".