Base | Representation |
---|---|
bin | 10000110100111001100… |
… | …001111101100111101001 |
3 | 11002112122022220122020102 |
4 | 100310321201331213221 |
5 | 122421111210011311 |
6 | 2243111354235145 |
7 | 146353321535015 |
oct | 20647141754751 |
9 | 4075568818212 |
10 | 1156311407081 |
11 | 40643070a656 |
12 | 168126425ab5 |
13 | 850692a69ac |
14 | 3dd74109545 |
15 | 2012949243b |
hex | 10d3987d9e9 |
1156311407081 has 2 divisors, whose sum is σ = 1156311407082. Its totient is φ = 1156311407080.
The previous prime is 1156311407057. The next prime is 1156311407099. The reversal of 1156311407081 is 1807041136511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1129084757056 + 27226650025 = 1062584^2 + 165005^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1156311407081 is a prime.
It is a super-2 number, since 2×11563114070812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1156311407021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 578155703540 + 578155703541.
It is an arithmetic number, because the mean of its divisors is an integer number (578155703541).
Almost surely, 21156311407081 is an apocalyptic number.
It is an amenable number.
1156311407081 is a deficient number, since it is larger than the sum of its proper divisors (1).
1156311407081 is an equidigital number, since it uses as much as digits as its factorization.
1156311407081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 38.
The spelling of 1156311407081 in words is "one trillion, one hundred fifty-six billion, three hundred eleven million, four hundred seven thousand, eighty-one".
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