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115717354371313 is a prime number
BaseRepresentation
bin11010010011111010001011…
…110011010011100011110001
3120011201110201101110201020021
4122103322023303103203301
5110131403120204340223
61050035452502043441
733242205626031202
oct3223721363234361
9504643641421207
10115717354371313
11339644aa885382
1210b8a96ba19581
134c7513b04c806
142080a6d7955a9
15d5a11986265d
hex693e8bcd38f1

115717354371313 has 2 divisors, whose sum is σ = 115717354371314. Its totient is φ = 115717354371312.

The previous prime is 115717354371271. The next prime is 115717354371323. The reversal of 115717354371313 is 313173453717511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 77592261970609 + 38125092400704 = 8808647^2 + 6174552^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115717354371313 is a prime.

It is a super-2 number, since 2×1157173543713132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115717354371323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57858677185656 + 57858677185657.

It is an arithmetic number, because the mean of its divisors is an integer number (57858677185657).

Almost surely, 2115717354371313 is an apocalyptic number.

It is an amenable number.

115717354371313 is a deficient number, since it is larger than the sum of its proper divisors (1).

115717354371313 is an equidigital number, since it uses as much as digits as its factorization.

115717354371313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2778300, while the sum is 52.

The spelling of 115717354371313 in words is "one hundred fifteen trillion, seven hundred seventeen billion, three hundred fifty-four million, three hundred seventy-one thousand, three hundred thirteen".