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115761442340833 is a prime number
BaseRepresentation
bin11010010100100011001111…
…101001100011111111100001
3120011212200111221202121200021
4122110203033221203333201
5110133113413214401313
61050112023352153441
733245326312423402
oct3224431751437741
9504780457677607
10115761442340833
1133981174341423
1210b97414998881
134c79346014443
142082c52c559a9
15d5b34a19978d
hex6948cfa63fe1

115761442340833 has 2 divisors, whose sum is σ = 115761442340834. Its totient is φ = 115761442340832.

The previous prime is 115761442340801. The next prime is 115761442340953. The reversal of 115761442340833 is 338043244167511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 74591343210384 + 41170099130449 = 8636628^2 + 6416393^2 .

It is an emirp because it is prime and its reverse (338043244167511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115761442340833 - 25 = 115761442340801 is a prime.

It is not a weakly prime, because it can be changed into another prime (115761442340333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57880721170416 + 57880721170417.

It is an arithmetic number, because the mean of its divisors is an integer number (57880721170417).

Almost surely, 2115761442340833 is an apocalyptic number.

It is an amenable number.

115761442340833 is a deficient number, since it is larger than the sum of its proper divisors (1).

115761442340833 is an equidigital number, since it uses as much as digits as its factorization.

115761442340833 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 52.

The spelling of 115761442340833 in words is "one hundred fifteen trillion, seven hundred sixty-one billion, four hundred forty-two million, three hundred forty thousand, eight hundred thirty-three".