Base | Representation |
---|---|
bin | 11010010101001001111111… |
… | …111100000101001001100001 |
3 | 120012000122220222202000200101 |
4 | 122111021333330011021201 |
5 | 110134304124000102123 |
6 | 1050143104445222401 |
7 | 33251331435522322 |
oct | 3225117774051141 |
9 | 505018828660611 |
10 | 115803054690913 |
11 | 33997888436997 |
12 | 10ba34a8861a01 |
13 | 4c80248134bb5 |
14 | 2084c7d610449 |
15 | d5c4834beaad |
hex | 69527ff05261 |
115803054690913 has 2 divisors, whose sum is σ = 115803054690914. Its totient is φ = 115803054690912.
The previous prime is 115803054690907. The next prime is 115803054690923. The reversal of 115803054690913 is 319096450308511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114222485250064 + 1580569440849 = 10687492^2 + 1257207^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115803054690913 is a prime.
It is not a weakly prime, because it can be changed into another prime (115803054690923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57901527345456 + 57901527345457.
It is an arithmetic number, because the mean of its divisors is an integer number (57901527345457).
Almost surely, 2115803054690913 is an apocalyptic number.
It is an amenable number.
115803054690913 is a deficient number, since it is larger than the sum of its proper divisors (1).
115803054690913 is an equidigital number, since it uses as much as digits as its factorization.
115803054690913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3499200, while the sum is 55.
The spelling of 115803054690913 in words is "one hundred fifteen trillion, eight hundred three billion, fifty-four million, six hundred ninety thousand, nine hundred thirteen".
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