Base | Representation |
---|---|
bin | 10000110110100000100… |
… | …010111001111000000010 |
3 | 11002201002210000101012122 |
4 | 100312200202321320002 |
5 | 122433131131112023 |
6 | 2243555053524242 |
7 | 146444206045466 |
oct | 20664042717002 |
9 | 4081083011178 |
10 | 1158039707138 |
11 | 407138252006 |
12 | 1685291a3682 |
13 | 85283381552 |
14 | 4009987a4a6 |
15 | 201cb0862c8 |
hex | 10da08b9e02 |
1158039707138 has 4 divisors (see below), whose sum is σ = 1737059560710. Its totient is φ = 579019853568.
The previous prime is 1158039707137. The next prime is 1158039707221. The reversal of 1158039707138 is 8317079308511.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 763584111889 + 394455595249 = 873833^2 + 628057^2 .
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 1158039707138.
It is not an unprimeable number, because it can be changed into a prime (1158039707137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 289509926783 + ... + 289509926786.
Almost surely, 21158039707138 is an apocalyptic number.
1158039707138 is a deficient number, since it is larger than the sum of its proper divisors (579019853572).
1158039707138 is an equidigital number, since it uses as much as digits as its factorization.
1158039707138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 579019853571.
The product of its (nonzero) digits is 1270080, while the sum is 53.
The spelling of 1158039707138 in words is "one trillion, one hundred fifty-eight billion, thirty-nine million, seven hundred seven thousand, one hundred thirty-eight".
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