Base | Representation |
---|---|
bin | 10101100100011111… |
… | …11100101101101011 |
3 | 1002220001200022111121 |
4 | 22302033330231223 |
5 | 142204044204013 |
6 | 5153041240111 |
7 | 556655166466 |
oct | 126217745553 |
9 | 32801608447 |
10 | 11580459883 |
11 | 4a0295aa03 |
12 | 22b2333037 |
13 | 1127271235 |
14 | 7bc00c2dd |
15 | 47b9ec58d |
hex | 2b23fcb6b |
11580459883 has 2 divisors, whose sum is σ = 11580459884. Its totient is φ = 11580459882.
The previous prime is 11580459833. The next prime is 11580459889. The reversal of 11580459883 is 38895408511.
It is a strong prime.
It is an emirp because it is prime and its reverse (38895408511) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11580459883 - 229 = 11043588971 is a prime.
It is a super-2 number, since 2×115804598832 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11580459883.
It is not a weakly prime, because it can be changed into another prime (11580459889) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5790229941 + 5790229942.
It is an arithmetic number, because the mean of its divisors is an integer number (5790229942).
Almost surely, 211580459883 is an apocalyptic number.
11580459883 is a deficient number, since it is larger than the sum of its proper divisors (1).
11580459883 is an equidigital number, since it uses as much as digits as its factorization.
11580459883 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1382400, while the sum is 52.
The spelling of 11580459883 in words is "eleven billion, five hundred eighty million, four hundred fifty-nine thousand, eight hundred eighty-three".
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