Base | Representation |
---|---|
bin | 1010100010001001110101… |
… | …0001111101011101101011 |
3 | 1112000012211110202211000210 |
4 | 2220202131101331131223 |
5 | 3004224132330424011 |
6 | 40344345441032203 |
7 | 2303522356303413 |
oct | 250423521753553 |
9 | 45005743684023 |
10 | 11581870561131 |
11 | 3765930aa1782 |
12 | 1370789025663 |
13 | 6602200a0a30 |
14 | 2c07cbb37643 |
15 | 15140eb016a6 |
hex | a889d47d76b |
11581870561131 has 32 divisors (see below), whose sum is σ = 16642528849408. Its totient is φ = 7122099571200.
The previous prime is 11581870561117. The next prime is 11581870561189. The reversal of 11581870561131 is 13116507818511.
It is not a de Polignac number, because 11581870561131 - 213 = 11581870552939 is a prime.
It is a super-2 number, since 2×115818705611312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11581870161131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 320038020 + ... + 320074206.
It is an arithmetic number, because the mean of its divisors is an integer number (520079026544).
Almost surely, 211581870561131 is an apocalyptic number.
11581870561131 is a deficient number, since it is larger than the sum of its proper divisors (5060658288277).
11581870561131 is a wasteful number, since it uses less digits than its factorization.
11581870561131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41971.
The product of its (nonzero) digits is 201600, while the sum is 48.
The spelling of 11581870561131 in words is "eleven trillion, five hundred eighty-one billion, eight hundred seventy million, five hundred sixty-one thousand, one hundred thirty-one".
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