Base | Representation |
---|---|
bin | 10101100101000110… |
… | …01011010100011001 |
3 | 1002220102011101211221 |
4 | 22302203023110121 |
5 | 142211342003231 |
6 | 5153341252041 |
7 | 560046062134 |
oct | 126243132431 |
9 | 32812141757 |
10 | 11585500441 |
11 | 4a05792a59 |
12 | 22b3b64021 |
13 | 1128317608 |
14 | 7bc96121b |
15 | 47c195d11 |
hex | 2b28cb519 |
11585500441 has 2 divisors, whose sum is σ = 11585500442. Its totient is φ = 11585500440.
The previous prime is 11585500427. The next prime is 11585500483. The reversal of 11585500441 is 14400558511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10692387216 + 893113225 = 103404^2 + 29885^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11585500441 is a prime.
It is a super-2 number, since 2×115855004412 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11585500397 and 11585500406.
It is not a weakly prime, because it can be changed into another prime (11585500541) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5792750220 + 5792750221.
It is an arithmetic number, because the mean of its divisors is an integer number (5792750221).
Almost surely, 211585500441 is an apocalyptic number.
It is an amenable number.
11585500441 is a deficient number, since it is larger than the sum of its proper divisors (1).
11585500441 is an equidigital number, since it uses as much as digits as its factorization.
11585500441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16000, while the sum is 34.
The spelling of 11585500441 in words is "eleven billion, five hundred eighty-five million, five hundred thousand, four hundred forty-one".
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