Base | Representation |
---|---|
bin | 10000111000010110110… |
… | …101111011010000110001 |
3 | 11002220020002120110220101 |
4 | 100320112311323100301 |
5 | 123001212221430131 |
6 | 2244524032512401 |
7 | 146544325515655 |
oct | 20702665732061 |
9 | 4086202513811 |
10 | 1160024405041 |
11 | 407a66597a07 |
12 | 1689a19ab701 |
13 | 8550b5cb8c8 |
14 | 402072b0a65 |
15 | 20295424c61 |
hex | 10e16d7b431 |
1160024405041 has 2 divisors, whose sum is σ = 1160024405042. Its totient is φ = 1160024405040.
The previous prime is 1160024405021. The next prime is 1160024405051. The reversal of 1160024405041 is 1405044200611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1112065157025 + 47959248016 = 1054545^2 + 218996^2 .
It is a cyclic number.
It is not a de Polignac number, because 1160024405041 - 231 = 1157876921393 is a prime.
It is not a weakly prime, because it can be changed into another prime (1160024405021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580012202520 + 580012202521.
It is an arithmetic number, because the mean of its divisors is an integer number (580012202521).
Almost surely, 21160024405041 is an apocalyptic number.
It is an amenable number.
1160024405041 is a deficient number, since it is larger than the sum of its proper divisors (1).
1160024405041 is an equidigital number, since it uses as much as digits as its factorization.
1160024405041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 1160024405041 its reverse (1405044200611), we get a palindrome (2565068605652).
The spelling of 1160024405041 in words is "one trillion, one hundred sixty billion, twenty-four million, four hundred five thousand, forty-one".
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