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116004292514881 is a prime number
BaseRepresentation
bin11010011000000101011010…
…101001011101010001000001
3120012201220100121012200102221
4122120011122221131101001
5110201103242340434011
61050415345234211041
733302014340020501
oct3230053251352101
9505656317180387
10116004292514881
1133a65164998601
12110164aaa23a81
134c96208a2c794
1420908cdc69a01
15d62810451971
hex69815aa5d441

116004292514881 has 2 divisors, whose sum is σ = 116004292514882. Its totient is φ = 116004292514880.

The previous prime is 116004292514861. The next prime is 116004292514987. The reversal of 116004292514881 is 188415292400611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113416003593025 + 2588288921856 = 10649695^2 + 1608816^2 .

It is a cyclic number.

It is not a de Polignac number, because 116004292514881 - 25 = 116004292514849 is a prime.

It is a super-3 number, since 3×1160042925148813 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (116004292514861) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58002146257440 + 58002146257441.

It is an arithmetic number, because the mean of its divisors is an integer number (58002146257441).

Almost surely, 2116004292514881 is an apocalyptic number.

It is an amenable number.

116004292514881 is a deficient number, since it is larger than the sum of its proper divisors (1).

116004292514881 is an equidigital number, since it uses as much as digits as its factorization.

116004292514881 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1105920, while the sum is 52.

The spelling of 116004292514881 in words is "one hundred sixteen trillion, four billion, two hundred ninety-two million, five hundred fourteen thousand, eight hundred eighty-one".