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11602113 = 33867371
BaseRepresentation
bin101100010000…
…100011000001
3210211110002220
4230100203001
510432231423
61052401253
7200421255
oct54204301
923743086
1011602113
116604926
123a76229
132532b73
141780265
1510429e3
hexb108c1

11602113 has 4 divisors (see below), whose sum is σ = 15469488. Its totient is φ = 7734740.

The previous prime is 11602111. The next prime is 11602159. The reversal of 11602113 is 31120611.

11602113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11602113 - 21 = 11602111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11602092 and 11602101.

It is not an unprimeable number, because it can be changed into a prime (11602111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1933683 + ... + 1933688.

It is an arithmetic number, because the mean of its divisors is an integer number (3867372).

Almost surely, 211602113 is an apocalyptic number.

It is an amenable number.

11602113 is a deficient number, since it is larger than the sum of its proper divisors (3867375).

11602113 is an equidigital number, since it uses as much as digits as its factorization.

11602113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3867374.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 11602113 is about 3406.1874581414. The cubic root of 11602113 is about 226.3839831948.

Adding to 11602113 its reverse (31120611), we get a palindrome (42722724).

The spelling of 11602113 in words is "eleven million, six hundred two thousand, one hundred thirteen".

Divisors: 1 3 3867371 11602113