Base | Representation |
---|---|
bin | 11010011001101011001011… |
… | …001111110011111110100011 |
3 | 120020010100101100100122221121 |
4 | 122121223023033303332203 |
5 | 110204401030241044341 |
6 | 1050541455305433111 |
7 | 33312633104433202 |
oct | 3231531317637643 |
9 | 506110340318847 |
10 | 116113555799971 |
11 | 33aa75341a1914 |
12 | 11033702a9b797 |
13 | 4ca35cc703ab2 |
14 | 2095cd7279239 |
15 | d655a7a234d1 |
hex | 699acb3f3fa3 |
116113555799971 has 2 divisors, whose sum is σ = 116113555799972. Its totient is φ = 116113555799970.
The previous prime is 116113555799963. The next prime is 116113555800001. The reversal of 116113555799971 is 179997555311611.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 116113555799971 - 23 = 116113555799963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 116113555799971.
It is not a weakly prime, because it can be changed into another prime (116113555799671) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58056777899985 + 58056777899986.
It is an arithmetic number, because the mean of its divisors is an integer number (58056777899986).
Almost surely, 2116113555799971 is an apocalyptic number.
116113555799971 is a deficient number, since it is larger than the sum of its proper divisors (1).
116113555799971 is an equidigital number, since it uses as much as digits as its factorization.
116113555799971 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 80372250, while the sum is 70.
The spelling of 116113555799971 in words is "one hundred sixteen trillion, one hundred thirteen billion, five hundred fifty-five million, seven hundred ninety-nine thousand, nine hundred seventy-one".
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