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1161316307 is a prime number
BaseRepresentation
bin100010100111000…
…0100011111010011
32222221012222111002
41011032010133103
54334244110212
6311123012215
740531011554
oct10516043723
92887188432
101161316307
11546595148
12284b0a06b
1315679bb18
14b034032b
156be48ac2
hex453847d3

1161316307 has 2 divisors, whose sum is σ = 1161316308. Its totient is φ = 1161316306.

The previous prime is 1161316259. The next prime is 1161316313. The reversal of 1161316307 is 7036131611.

It is a strong prime.

It is an emirp because it is prime and its reverse (7036131611) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1161316307 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1161316307.

It is not a weakly prime, because it can be changed into another prime (1161316357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580658153 + 580658154.

It is an arithmetic number, because the mean of its divisors is an integer number (580658154).

Almost surely, 21161316307 is an apocalyptic number.

1161316307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1161316307 is an equidigital number, since it uses as much as digits as its factorization.

1161316307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2268, while the sum is 29.

The square root of 1161316307 is about 34078.0913051186. The cubic root of 1161316307 is about 1051.1148572813.

Adding to 1161316307 its reverse (7036131611), we get a palindrome (8197447918).

The spelling of 1161316307 in words is "one billion, one hundred sixty-one million, three hundred sixteen thousand, three hundred seven".