Base | Representation |
---|---|
bin | 1010100011111110100011… |
… | …1110101111011011100001 |
3 | 1112010012201020201122111222 |
4 | 2220333220332233123201 |
5 | 3010232321033044101 |
6 | 40411011034344425 |
7 | 2306012024566226 |
oct | 250775076573341 |
9 | 45105636648458 |
10 | 11613205362401 |
11 | 3778150742755 |
12 | 1376872b8b115 |
13 | 663174b67266 |
14 | 2c212156194d |
15 | 1521459e201b |
hex | a8fe8faf6e1 |
11613205362401 has 2 divisors, whose sum is σ = 11613205362402. Its totient is φ = 11613205362400.
The previous prime is 11613205362391. The next prime is 11613205362427. The reversal of 11613205362401 is 10426350231611.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7518147221776 + 4095058140625 = 2741924^2 + 2023625^2 .
It is a cyclic number.
It is not a de Polignac number, because 11613205362401 - 226 = 11613138253537 is a prime.
It is not a weakly prime, because it can be changed into another prime (11613205362491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806602681200 + 5806602681201.
It is an arithmetic number, because the mean of its divisors is an integer number (5806602681201).
Almost surely, 211613205362401 is an apocalyptic number.
It is an amenable number.
11613205362401 is a deficient number, since it is larger than the sum of its proper divisors (1).
11613205362401 is an equidigital number, since it uses as much as digits as its factorization.
11613205362401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 11613205362401 in words is "eleven trillion, six hundred thirteen billion, two hundred five million, three hundred sixty-two thousand, four hundred one".
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