Base | Representation |
---|---|
bin | 1010100011111110101010… |
… | …0110000110000101010011 |
3 | 1112010012210010201010222022 |
4 | 2220333222212012011103 |
5 | 3010232400002043034 |
6 | 40411013443202055 |
7 | 2306012504101325 |
oct | 250775246060523 |
9 | 45105703633868 |
10 | 11613232456019 |
11 | 3778164a68577 |
12 | 137688007632b |
13 | 66317a66239c |
14 | 2c2124db5615 |
15 | 152148094b2e |
hex | a8fea986153 |
11613232456019 has 2 divisors, whose sum is σ = 11613232456020. Its totient is φ = 11613232456018.
The previous prime is 11613232455991. The next prime is 11613232456087. The reversal of 11613232456019 is 91065423231611.
11613232456019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11613232456019 - 228 = 11612964020563 is a prime.
It is a super-2 number, since 2×116132324560192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11613232456919) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806616228009 + 5806616228010.
It is an arithmetic number, because the mean of its divisors is an integer number (5806616228010).
Almost surely, 211613232456019 is an apocalyptic number.
11613232456019 is a deficient number, since it is larger than the sum of its proper divisors (1).
11613232456019 is an equidigital number, since it uses as much as digits as its factorization.
11613232456019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 233280, while the sum is 44.
The spelling of 11613232456019 in words is "eleven trillion, six hundred thirteen billion, two hundred thirty-two million, four hundred fifty-six thousand, nineteen".
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