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1161330403153 = 1987584464219
BaseRepresentation
bin10000111001100100101…
…011111010011101010001
311010000121010001001111211
4100321210223322131101
5123011401040400103
62245301404540121
7146621564360434
oct20714453723521
94100533031454
101161330403153
11408576811698
121690a7251641
1385689056a5b
14402cc91381b
152031edec36d
hex10e64afa751

1161330403153 has 4 divisors (see below), whose sum is σ = 1161914869360. Its totient is φ = 1160745936948.

The previous prime is 1161330403117. The next prime is 1161330403187. The reversal of 1161330403153 is 3513040331611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1161330403153 - 237 = 1023891449681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1161330403553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 292230123 + ... + 292234096.

It is an arithmetic number, because the mean of its divisors is an integer number (290478717340).

Almost surely, 21161330403153 is an apocalyptic number.

It is an amenable number.

1161330403153 is a deficient number, since it is larger than the sum of its proper divisors (584466207).

1161330403153 is an equidigital number, since it uses as much as digits as its factorization.

1161330403153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 584466206.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 1161330403153 its reverse (3513040331611), we get a palindrome (4674370734764).

The spelling of 1161330403153 in words is "one trillion, one hundred sixty-one billion, three hundred thirty million, four hundred three thousand, one hundred fifty-three".

Divisors: 1 1987 584464219 1161330403153