Base | Representation |
---|---|
bin | 10101101000101000… |
… | …01100011001100001 |
3 | 1002222110220121000222 |
4 | 22310110030121201 |
5 | 142241433032022 |
6 | 5200320252425 |
7 | 560555644265 |
oct | 126424143141 |
9 | 32873817028 |
10 | 11615127137 |
11 | 4a20488a29 |
12 | 2301a71115 |
13 | 11314bb6c3 |
14 | 7c28740a5 |
15 | 47ea99242 |
hex | 2b450c661 |
11615127137 has 2 divisors, whose sum is σ = 11615127138. Its totient is φ = 11615127136.
The previous prime is 11615127119. The next prime is 11615127221. The reversal of 11615127137 is 73172151611.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10591703056 + 1023424081 = 102916^2 + 31991^2 .
It is a cyclic number.
It is not a de Polignac number, because 11615127137 - 28 = 11615126881 is a prime.
It is a super-2 number, since 2×116151271372 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11615127097 and 11615127106.
It is not a weakly prime, because it can be changed into another prime (11615127037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5807563568 + 5807563569.
It is an arithmetic number, because the mean of its divisors is an integer number (5807563569).
Almost surely, 211615127137 is an apocalyptic number.
It is an amenable number.
11615127137 is a deficient number, since it is larger than the sum of its proper divisors (1).
11615127137 is an equidigital number, since it uses as much as digits as its factorization.
11615127137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8820, while the sum is 35.
Adding to 11615127137 its reverse (73172151611), we get a palindrome (84787278748).
The spelling of 11615127137 in words is "eleven billion, six hundred fifteen million, one hundred twenty-seven thousand, one hundred thirty-seven".
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