Base | Representation |
---|---|
bin | 11010011010010001110011… |
… | …000010011111010101111011 |
3 | 120020021022102110002001012022 |
4 | 122122101303002133111323 |
5 | 110211040443022214111 |
6 | 1051012514311105055 |
7 | 33315631550001122 |
oct | 3232216302372573 |
9 | 506238373061168 |
10 | 116155025585531 |
11 | 34013084873569 |
12 | 1103b75707218b |
13 | 4ca74ab129b4a |
14 | 2097d0cb22ab9 |
15 | d666d35872db |
hex | 69a47309f57b |
116155025585531 has 2 divisors, whose sum is σ = 116155025585532. Its totient is φ = 116155025585530.
The previous prime is 116155025585513. The next prime is 116155025585609. The reversal of 116155025585531 is 135585520551611.
Together with previous prime (116155025585513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-116155025585531 is a prime.
It is a super-2 number, since 2×1161550255855312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (116155025581531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58077512792765 + 58077512792766.
It is an arithmetic number, because the mean of its divisors is an integer number (58077512792766).
Almost surely, 2116155025585531 is an apocalyptic number.
116155025585531 is a deficient number, since it is larger than the sum of its proper divisors (1).
116155025585531 is an equidigital number, since it uses as much as digits as its factorization.
116155025585531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4500000, while the sum is 53.
The spelling of 116155025585531 in words is "one hundred sixteen trillion, one hundred fifty-five billion, twenty-five million, five hundred eighty-five thousand, five hundred thirty-one".
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