Base | Representation |
---|---|
bin | 11010011010010010110100… |
… | …001010000110101100111001 |
3 | 120020021102020120211120101112 |
4 | 122122102310022012230321 |
5 | 110211100212213211133 |
6 | 1051013214535330105 |
7 | 33316000614141611 |
oct | 3232226412065471 |
9 | 506242216746345 |
10 | 116156118100793 |
11 | 34013595536441 |
12 | 1103ba00b20935 |
13 | 4ca7623589a94 |
14 | 2097db3c73a41 |
15 | d66749440648 |
hex | 69a4b4286b39 |
116156118100793 has 2 divisors, whose sum is σ = 116156118100794. Its totient is φ = 116156118100792.
The previous prime is 116156118100733. The next prime is 116156118100801. The reversal of 116156118100793 is 397001811651611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101750958260224 + 14405159840569 = 10087168^2 + 3795413^2 .
It is a cyclic number.
It is not a de Polignac number, because 116156118100793 - 244 = 98563932056377 is a prime.
It is not a weakly prime, because it can be changed into another prime (116156118100733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58078059050396 + 58078059050397.
It is an arithmetic number, because the mean of its divisors is an integer number (58078059050397).
Almost surely, 2116156118100793 is an apocalyptic number.
It is an amenable number.
116156118100793 is a deficient number, since it is larger than the sum of its proper divisors (1).
116156118100793 is an equidigital number, since it uses as much as digits as its factorization.
116156118100793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 50.
The spelling of 116156118100793 in words is "one hundred sixteen trillion, one hundred fifty-six billion, one hundred eighteen million, one hundred thousand, seven hundred ninety-three".
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