Base | Representation |
---|---|
bin | 11010011011011001110100… |
… | …110111011011000001010011 |
3 | 120020112201001102001101121121 |
4 | 122123121310313123001103 |
5 | 110213322341101300003 |
6 | 1051112224525103111 |
7 | 33324340242463501 |
oct | 3233316467330123 |
9 | 506481042041547 |
10 | 116232365650003 |
11 | 34042962268719 |
12 | 110527400b7a97 |
13 | 4cb18851651c5 |
14 | 209b9684d7671 |
15 | d6870d286cbd |
hex | 69b674ddb053 |
116232365650003 has 4 divisors (see below), whose sum is σ = 116232389962920. Its totient is φ = 116232341337088.
The previous prime is 116232365649979. The next prime is 116232365650019. The reversal of 116232365650003 is 300056563232611.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 116232365650003 - 25 = 116232365649971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (116232365650703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2346793 + ... + 15426346.
It is an arithmetic number, because the mean of its divisors is an integer number (29058097490730).
Almost surely, 2116232365650003 is an apocalyptic number.
116232365650003 is a deficient number, since it is larger than the sum of its proper divisors (24312917).
116232365650003 is an equidigital number, since it uses as much as digits as its factorization.
116232365650003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24312916.
The product of its (nonzero) digits is 583200, while the sum is 43.
The spelling of 116232365650003 in words is "one hundred sixteen trillion, two hundred thirty-two billion, three hundred sixty-five million, six hundred fifty thousand, three".
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