11630054113 has 2 divisors, whose sum is σ = 11630054114. Its totient is φ = 11630054112.

The previous prime is 11630054089. The next prime is 11630054143. The reversal of 11630054113 is 31145003611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5958759249 + 5671294864 = 77193^2 + 75308^2 .

It is an emirp because it is prime and its reverse (31145003611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11630054113 - 2⁵ = 11630054081 is a prime.

It is not a weakly prime, because it can be changed into another prime (11630054143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5815027056 + 5815027057.

It is an arithmetic number, because the mean of its divisors is an integer number (5815027057).

Almost surely, 2^11630054113 is an apocalyptic number.

It is an amenable number.

11630054113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11630054113 is an equidigital number, since it uses as much as digits as its factorization.

11630054113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 11630054113 its reverse (31145003611), we get a palindrome (42775057724).

The spelling of 11630054113 in words is "eleven billion, six hundred thirty million, fifty-four thousand, one hundred thirteen".