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116306043313 = 269514315463
BaseRepresentation
bin110110001010001100…
…0010110000110110001
3102010012120100011112211
41230110120112012301
53401143321341223
6125232534052121
711255113025245
oct1542430260661
9363176304484
10116306043313
1145363802859
121a65a7aa041
13ac76acb395
1458b48da425
15305aa34d0d
hex1b146161b1

116306043313 has 4 divisors (see below), whose sum is σ = 116310385728. Its totient is φ = 116301700900.

The previous prime is 116306043289. The next prime is 116306043323. The reversal of 116306043313 is 313340603611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 116306043313 - 217 = 116305912241 is a prime.

It is a super-2 number, since 2×1163060433132 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (116306043323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2130781 + ... + 2184682.

It is an arithmetic number, because the mean of its divisors is an integer number (29077596432).

Almost surely, 2116306043313 is an apocalyptic number.

It is an amenable number.

116306043313 is a deficient number, since it is larger than the sum of its proper divisors (4342415).

116306043313 is an equidigital number, since it uses as much as digits as its factorization.

116306043313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4342414.

The product of its (nonzero) digits is 11664, while the sum is 31.

Adding to 116306043313 its reverse (313340603611), we get a palindrome (429646646924).

The spelling of 116306043313 in words is "one hundred sixteen billion, three hundred six million, forty-three thousand, three hundred thirteen".

Divisors: 1 26951 4315463 116306043313