Base | Representation |
---|---|
bin | 11010011110111100010101… |
… | …010010110101111001011001 |
3 | 120021101221211010000211111202 |
4 | 122132330111102311321121 |
5 | 110231313434243023423 |
6 | 1051420050213203545 |
7 | 33351040224065603 |
oct | 3236742522657131 |
9 | 507357733024452 |
10 | 116475575361113 |
11 | 34127017863371 |
12 | 110918b66305b5 |
13 | 4ccb7a44c5677 |
14 | 20a963b17c173 |
15 | d6ebe4dad728 |
hex | 69ef154b5e59 |
116475575361113 has 2 divisors, whose sum is σ = 116475575361114. Its totient is φ = 116475575361112.
The previous prime is 116475575361091. The next prime is 116475575361133. The reversal of 116475575361113 is 311163575574611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108488327187529 + 7987248173584 = 10415773^2 + 2826172^2 .
It is a cyclic number.
It is not a de Polignac number, because 116475575361113 - 216 = 116475575295577 is a prime.
It is not a weakly prime, because it can be changed into another prime (116475575361133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58237787680556 + 58237787680557.
It is an arithmetic number, because the mean of its divisors is an integer number (58237787680557).
Almost surely, 2116475575361113 is an apocalyptic number.
It is an amenable number.
116475575361113 is a deficient number, since it is larger than the sum of its proper divisors (1).
116475575361113 is an equidigital number, since it uses as much as digits as its factorization.
116475575361113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7938000, while the sum is 56.
The spelling of 116475575361113 in words is "one hundred sixteen trillion, four hundred seventy-five billion, five hundred seventy-five million, three hundred sixty-one thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •