Base | Representation |
---|---|
bin | 10101101110111000… |
… | …01000100011100001 |
3 | 1010010010112110020021 |
4 | 22313130020203201 |
5 | 142343342241233 |
6 | 5205431513441 |
7 | 562063312111 |
oct | 126734104341 |
9 | 33103473207 |
10 | 11667540193 |
11 | 4a48027701 |
12 | 2317528881 |
13 | 113c31024a |
14 | 7c97d9041 |
15 | 48449de2d |
hex | 2b77088e1 |
11667540193 has 2 divisors, whose sum is σ = 11667540194. Its totient is φ = 11667540192.
The previous prime is 11667540187. The next prime is 11667540223. The reversal of 11667540193 is 39104576611.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10061694864 + 1605845329 = 100308^2 + 40073^2 .
It is a cyclic number.
It is not a de Polignac number, because 11667540193 - 25 = 11667540161 is a prime.
It is a super-2 number, since 2×116675401932 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11667540593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5833770096 + 5833770097.
It is an arithmetic number, because the mean of its divisors is an integer number (5833770097).
Almost surely, 211667540193 is an apocalyptic number.
It is an amenable number.
11667540193 is a deficient number, since it is larger than the sum of its proper divisors (1).
11667540193 is an equidigital number, since it uses as much as digits as its factorization.
11667540193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 11667540193 in words is "eleven billion, six hundred sixty-seven million, five hundred forty thousand, one hundred ninety-three".
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