Base | Representation |
---|---|
bin | 1101111101000… |
… | …00101101111001 |
3 | 22011020202201211 |
4 | 12332200231321 |
5 | 214431101413 |
6 | 15340443121 |
7 | 2620624216 |
oct | 676405571 |
9 | 264222654 |
10 | 117050233 |
11 | 60087633 |
12 | 332494a1 |
13 | 1b3333c1 |
14 | 1178cb0d |
15 | a42183d |
hex | 6fa0b79 |
117050233 has 2 divisors, whose sum is σ = 117050234. Its totient is φ = 117050232.
The previous prime is 117050221. The next prime is 117050237. The reversal of 117050233 is 332050711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79067664 + 37982569 = 8892^2 + 6163^2 .
It is an emirp because it is prime and its reverse (332050711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 117050233 - 25 = 117050201 is a prime.
It is a super-3 number, since 3×1170502333 (a number of 25 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (117050237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58525116 + 58525117.
It is an arithmetic number, because the mean of its divisors is an integer number (58525117).
Almost surely, 2117050233 is an apocalyptic number.
It is an amenable number.
117050233 is a deficient number, since it is larger than the sum of its proper divisors (1).
117050233 is an equidigital number, since it uses as much as digits as its factorization.
117050233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 630, while the sum is 22.
The square root of 117050233 is about 10818.9755984566. The cubic root of 117050233 is about 489.1673112908.
The spelling of 117050233 in words is "one hundred seventeen million, fifty thousand, two hundred thirty-three".
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