Base | Representation |
---|---|
bin | 10101110011010111… |
… | …01111111000110001 |
3 | 1010012202101011011101 |
4 | 22321223233320301 |
5 | 142433012003024 |
6 | 5213254444401 |
7 | 563031312133 |
oct | 127153577061 |
9 | 33182334141 |
10 | 11705187889 |
11 | 4a673009aa |
12 | 2328063701 |
13 | 11470621a5 |
14 | 7d07d9053 |
15 | 487938c44 |
hex | 2b9aefe31 |
11705187889 has 2 divisors, whose sum is σ = 11705187890. Its totient is φ = 11705187888.
The previous prime is 11705187883. The next prime is 11705187931. The reversal of 11705187889 is 98878150711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8636914225 + 3068273664 = 92935^2 + 55392^2 .
It is a cyclic number.
It is not a de Polignac number, because 11705187889 - 217 = 11705056817 is a prime.
It is a super-3 number, since 3×117051878893 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11705187883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5852593944 + 5852593945.
It is an arithmetic number, because the mean of its divisors is an integer number (5852593945).
Almost surely, 211705187889 is an apocalyptic number.
It is an amenable number.
11705187889 is a deficient number, since it is larger than the sum of its proper divisors (1).
11705187889 is an equidigital number, since it uses as much as digits as its factorization.
11705187889 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1128960, while the sum is 55.
The spelling of 11705187889 in words is "eleven billion, seven hundred five million, one hundred eighty-seven thousand, eight hundred eighty-nine".
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