Base | Representation |
---|---|
bin | 10101110100010100… |
… | …11000111001000011 |
3 | 1010020022111020101000 |
4 | 22322022120321003 |
5 | 142442041021123 |
6 | 5214142543043 |
7 | 563156504631 |
oct | 127212307103 |
9 | 33208436330 |
10 | 11713220163 |
11 | 4a70897747 |
12 | 232a897a83 |
13 | 1148915208 |
14 | 7d18ca351 |
15 | 4884c3b43 |
hex | 2ba298e43 |
11713220163 has 8 divisors (see below), whose sum is σ = 17352918800. Its totient is φ = 7808813424.
The previous prime is 11713220161. The next prime is 11713220171. The reversal of 11713220163 is 36102231711.
It is not a de Polignac number, because 11713220163 - 21 = 11713220161 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 433822969 = 11713220163 / (1 + 1 + 7 + 1 + 3 + 2 + 2 + 0 + 1 + 6 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11713220161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 216911458 + ... + 216911511.
It is an arithmetic number, because the mean of its divisors is an integer number (2169114850).
Almost surely, 211713220163 is an apocalyptic number.
11713220163 is a deficient number, since it is larger than the sum of its proper divisors (5639698637).
11713220163 is an equidigital number, since it uses as much as digits as its factorization.
11713220163 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433822978 (or 433822972 counting only the distinct ones).
The product of its (nonzero) digits is 1512, while the sum is 27.
Adding to 11713220163 its reverse (36102231711), we get a palindrome (47815451874).
The spelling of 11713220163 in words is "eleven billion, seven hundred thirteen million, two hundred twenty thousand, one hundred sixty-three".
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