Base | Representation |
---|---|
bin | 110110100111111011… |
… | …1001111111001010001 |
3 | 102012210010011121212121 |
4 | 1231033313033321101 |
5 | 3410214311000311 |
6 | 125515543454241 |
7 | 11321621356222 |
oct | 1551767177121 |
9 | 365703147777 |
10 | 117304000081 |
11 | 45826060514 |
12 | 1a898a57381 |
13 | b0a57a1548 |
14 | 596b275249 |
15 | 30b8460b71 |
hex | 1b4fdcfe51 |
117304000081 has 2 divisors, whose sum is σ = 117304000082. Its totient is φ = 117304000080.
The previous prime is 117304000039. The next prime is 117304000111. The reversal of 117304000081 is 180000403711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117302825025 + 1175056 = 342495^2 + 1084^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-117304000081 is a prime.
It is a super-2 number, since 2×1173040000812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (117304000001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58652000040 + 58652000041.
It is an arithmetic number, because the mean of its divisors is an integer number (58652000041).
Almost surely, 2117304000081 is an apocalyptic number.
It is an amenable number.
117304000081 is a deficient number, since it is larger than the sum of its proper divisors (1).
117304000081 is an equidigital number, since it uses as much as digits as its factorization.
117304000081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
Adding to 117304000081 its reverse (180000403711), we get a palindrome (297304403792).
The spelling of 117304000081 in words is "one hundred seventeen billion, three hundred four million, eighty-one", and thus it is an aban number.
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