Base | Representation |
---|---|
bin | 1010101011000000001011… |
… | …1100101101101010000001 |
3 | 1112112202020200012202001022 |
4 | 2222300002330231222001 |
5 | 3014222011412412003 |
6 | 40542251310115225 |
7 | 2320513661251064 |
oct | 252600274555201 |
9 | 45482220182038 |
10 | 11733900122753 |
11 | 3814356798586 |
12 | 13961374abb15 |
13 | 67166ac77b13 |
14 | 2c7cd0c7a8db |
15 | 15535b982738 |
hex | aac02f2da81 |
11733900122753 has 2 divisors, whose sum is σ = 11733900122754. Its totient is φ = 11733900122752.
The previous prime is 11733900122741. The next prime is 11733900122803. The reversal of 11733900122753 is 35722100933711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11278662490384 + 455237632369 = 3358372^2 + 674713^2 .
It is a cyclic number.
It is not a de Polignac number, because 11733900122753 - 26 = 11733900122689 is a prime.
It is not a weakly prime, because it can be changed into another prime (11733900122453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5866950061376 + 5866950061377.
It is an arithmetic number, because the mean of its divisors is an integer number (5866950061377).
Almost surely, 211733900122753 is an apocalyptic number.
It is an amenable number.
11733900122753 is a deficient number, since it is larger than the sum of its proper divisors (1).
11733900122753 is an equidigital number, since it uses as much as digits as its factorization.
11733900122753 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 238140, while the sum is 44.
The spelling of 11733900122753 in words is "eleven trillion, seven hundred thirty-three billion, nine hundred million, one hundred twenty-two thousand, seven hundred fifty-three".
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