117345433 has 2 divisors, whose sum is σ = 117345434. Its totient is φ = 117345432.

The previous prime is 117345421. The next prime is 117345443. The reversal of 117345433 is 334543711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111450249 + 5895184 = 10557^2 + 2428^2 .

It is an emirp because it is prime and its reverse (334543711) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 117345433 - 2⁹ = 117344921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 117345395 and 117345404.

It is not a weakly prime, because it can be changed into another prime (117345443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58672716 + 58672717.

It is an arithmetic number, because the mean of its divisors is an integer number (58672717).

Almost surely, 2^117345433 is an apocalyptic number.

It is an amenable number.

117345433 is a deficient number, since it is larger than the sum of its proper divisors (1).

117345433 is an equidigital number, since it uses as much as digits as its factorization.

117345433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 15120, while the sum is 31.

The square root of 117345433 is about 10832.6097040372. The cubic root of 117345433 is about 489.5781917665.

The spelling of 117345433 in words is "one hundred seventeen million, three hundred forty-five thousand, four hundred thirty-three".