Base | Representation |
---|---|
bin | 11010101011111110010010… |
… | …110101110100110111001011 |
3 | 120101120120011020002122121212 |
4 | 122223332102311310313023 |
5 | 110341001334412201413 |
6 | 1053343301542323335 |
7 | 33502530442322315 |
oct | 3253762265646713 |
9 | 511516136078555 |
10 | 117371034881483 |
11 | 3444185a374659 |
12 | 111b736212954b |
13 | 506506c3a4026 |
14 | 20dab0751c7b5 |
15 | d881539a2ca8 |
hex | 6abf92d74dcb |
117371034881483 has 2 divisors, whose sum is σ = 117371034881484. Its totient is φ = 117371034881482.
The previous prime is 117371034881467. The next prime is 117371034881533. The reversal of 117371034881483 is 384188430173711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117371034881483 - 24 = 117371034881467 is a prime.
It is a super-3 number, since 3×1173710348814833 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (117371034881083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58685517440741 + 58685517440742.
It is an arithmetic number, because the mean of its divisors is an integer number (58685517440742).
Almost surely, 2117371034881483 is an apocalyptic number.
117371034881483 is a deficient number, since it is larger than the sum of its proper divisors (1).
117371034881483 is an equidigital number, since it uses as much as digits as its factorization.
117371034881483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10838016, while the sum is 59.
The spelling of 117371034881483 in words is "one hundred seventeen trillion, three hundred seventy-one billion, thirty-four million, eight hundred eighty-one thousand, four hundred eighty-three".
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