Base | Representation |
---|---|
bin | 1101111111111… |
… | …01101111000001 |
3 | 22011222010100221 |
4 | 12333331233001 |
5 | 220030244413 |
6 | 15352543041 |
7 | 2624102053 |
oct | 677755701 |
9 | 264863327 |
10 | 117431233 |
11 | 60317907 |
12 | 333b1a81 |
13 | 1b43794a |
14 | 1184b8d3 |
15 | a49968d |
hex | 6ffdbc1 |
117431233 has 2 divisors, whose sum is σ = 117431234. Its totient is φ = 117431232.
The previous prime is 117431219. The next prime is 117431243. The reversal of 117431233 is 332134711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110313009 + 7118224 = 10503^2 + 2668^2 .
It is a cyclic number.
It is not a de Polignac number, because 117431233 - 25 = 117431201 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 117431198 and 117431207.
It is not a weakly prime, because it can be changed into another prime (117431203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58715616 + 58715617.
It is an arithmetic number, because the mean of its divisors is an integer number (58715617).
Almost surely, 2117431233 is an apocalyptic number.
It is an amenable number.
117431233 is a deficient number, since it is larger than the sum of its proper divisors (1).
117431233 is an equidigital number, since it uses as much as digits as its factorization.
117431233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1512, while the sum is 25.
The square root of 117431233 is about 10836.5692449225. The cubic root of 117431233 is about 489.6974850760.
Adding to 117431233 its reverse (332134711), we get a palindrome (449565944).
The spelling of 117431233 in words is "one hundred seventeen million, four hundred thirty-one thousand, two hundred thirty-three".
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