Base | Representation |
---|---|
bin | 1110000000011… |
… | …01001111010001 |
3 | 22012002100110221 |
4 | 13000031033101 |
5 | 220034312422 |
6 | 15354153041 |
7 | 2624455153 |
oct | 700151721 |
9 | 265070427 |
10 | 117494737 |
11 | 60360598 |
12 | 33422781 |
13 | 1b45a819 |
14 | 11866ad3 |
15 | a4ad3c7 |
hex | 700d3d1 |
117494737 has 2 divisors, whose sum is σ = 117494738. Its totient is φ = 117494736.
The previous prime is 117494669. The next prime is 117494749. The reversal of 117494737 is 737494711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 117483921 + 10816 = 10839^2 + 104^2 .
It is an emirp because it is prime and its reverse (737494711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 117494737 - 211 = 117492689 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 117494693 and 117494702.
It is not a weakly prime, because it can be changed into another prime (117494437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58747368 + 58747369.
It is an arithmetic number, because the mean of its divisors is an integer number (58747369).
Almost surely, 2117494737 is an apocalyptic number.
It is an amenable number.
117494737 is a deficient number, since it is larger than the sum of its proper divisors (1).
117494737 is an equidigital number, since it uses as much as digits as its factorization.
117494737 is an evil number, because the sum of its binary digits is even.
The product of its digits is 148176, while the sum is 43.
The square root of 117494737 is about 10839.4989275335. The cubic root of 117494737 is about 489.7857413951.
The spelling of 117494737 in words is "one hundred seventeen million, four hundred ninety-four thousand, seven hundred thirty-seven".
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