Base | Representation |
---|---|
bin | 1010101100101110011010… |
… | …0001101110010000000001 |
3 | 1112122120121201010111112201 |
4 | 2223023212201232100001 |
5 | 3020213110420300241 |
6 | 41004023302153201 |
7 | 2322612125451061 |
oct | 253134641562001 |
9 | 45576551114481 |
10 | 11763488056321 |
11 | 382595a374a41 |
12 | 139ba14422801 |
13 | 6743a4b65311 |
14 | 2c94da69d3a1 |
15 | 155ede312931 |
hex | ab2e686e401 |
11763488056321 has 4 divisors (see below), whose sum is σ = 11763634436032. Its totient is φ = 11763341676612.
The previous prime is 11763488056279. The next prime is 11763488056337. The reversal of 11763488056321 is 12365088436711.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11763488056321 - 225 = 11763454501889 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11763488056391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73069245 + ... + 73230058.
It is an arithmetic number, because the mean of its divisors is an integer number (2940908609008).
Almost surely, 211763488056321 is an apocalyptic number.
It is an amenable number.
11763488056321 is a deficient number, since it is larger than the sum of its proper divisors (146379711).
11763488056321 is an equidigital number, since it uses as much as digits as its factorization.
11763488056321 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 146379710.
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 11763488056321 in words is "eleven trillion, seven hundred sixty-three billion, four hundred eighty-eight million, fifty-six thousand, three hundred twenty-one".
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