Base | Representation |
---|---|
bin | 10101111011101011… |
… | …11001001111000001 |
3 | 1010101121122202200022 |
4 | 22331311321033001 |
5 | 143103342101411 |
6 | 5224230103225 |
7 | 564536323121 |
oct | 127565711701 |
9 | 33347582608 |
10 | 11774956481 |
11 | 4aa27240a2 |
12 | 23474aab15 |
13 | 115864c592 |
14 | 7d9b9ac81 |
15 | 48db1aedb |
hex | 2bdd793c1 |
11774956481 has 2 divisors, whose sum is σ = 11774956482. Its totient is φ = 11774956480.
The previous prime is 11774956477. The next prime is 11774956493. The reversal of 11774956481 is 18465947711.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7234353025 + 4540603456 = 85055^2 + 67384^2 .
It is an emirp because it is prime and its reverse (18465947711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11774956481 - 22 = 11774956477 is a prime.
It is a super-2 number, since 2×117749564812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11774956451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5887478240 + 5887478241.
It is an arithmetic number, because the mean of its divisors is an integer number (5887478241).
Almost surely, 211774956481 is an apocalyptic number.
It is an amenable number.
11774956481 is a deficient number, since it is larger than the sum of its proper divisors (1).
11774956481 is an equidigital number, since it uses as much as digits as its factorization.
11774956481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1693440, while the sum is 53.
The spelling of 11774956481 in words is "eleven billion, seven hundred seventy-four million, nine hundred fifty-six thousand, four hundred eighty-one".
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