Base | Representation |
---|---|
bin | 11010110010010101101011… |
… | …100011000011001011010011 |
3 | 120110010101020021222111102101 |
4 | 122302111223203003023103 |
5 | 110420133212322442042 |
6 | 1054320243242301231 |
7 | 33546244343201065 |
oct | 3262255343031323 |
9 | 513111207874371 |
10 | 117808462312147 |
11 | 345a0319795632 |
12 | 1126809b7b7817 |
13 | 50973a0b07339 |
14 | 2113d6234b735 |
15 | d947060c06b7 |
hex | 6b256b8c32d3 |
117808462312147 has 2 divisors, whose sum is σ = 117808462312148. Its totient is φ = 117808462312146.
The previous prime is 117808462312139. The next prime is 117808462312159. The reversal of 117808462312147 is 741213264808711.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 117808462312147 - 23 = 117808462312139 is a prime.
It is not a weakly prime, because it can be changed into another prime (117808462313147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58904231156073 + 58904231156074.
It is an arithmetic number, because the mean of its divisors is an integer number (58904231156074).
Almost surely, 2117808462312147 is an apocalyptic number.
117808462312147 is a deficient number, since it is larger than the sum of its proper divisors (1).
117808462312147 is an equidigital number, since it uses as much as digits as its factorization.
117808462312147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3612672, while the sum is 55.
The spelling of 117808462312147 in words is "one hundred seventeen trillion, eight hundred eight billion, four hundred sixty-two million, three hundred twelve thousand, one hundred forty-seven".
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