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117808462312417 is a prime number
BaseRepresentation
bin11010110010010101101011…
…100011000011001111100001
3120110010101020021222111210101
4122302111223203003033201
5110420133212322444132
61054320243242302401
733546244343201632
oct3262255343031741
9513111207874711
10117808462312417
11345a0319795858
121126809b7b7a01
1350973a0b074b6
142113d6234b889
15d947060c07e7
hex6b256b8c33e1

117808462312417 has 2 divisors, whose sum is σ = 117808462312418. Its totient is φ = 117808462312416.

The previous prime is 117808462312367. The next prime is 117808462312459. The reversal of 117808462312417 is 714213264808711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75942179099361 + 41866283213056 = 8714481^2 + 6470416^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-117808462312417 is a prime.

It is not a weakly prime, because it can be changed into another prime (117808462372417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58904231156208 + 58904231156209.

It is an arithmetic number, because the mean of its divisors is an integer number (58904231156209).

Almost surely, 2117808462312417 is an apocalyptic number.

It is an amenable number.

117808462312417 is a deficient number, since it is larger than the sum of its proper divisors (1).

117808462312417 is an equidigital number, since it uses as much as digits as its factorization.

117808462312417 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3612672, while the sum is 55.

The spelling of 117808462312417 in words is "one hundred seventeen trillion, eight hundred eight billion, four hundred sixty-two million, three hundred twelve thousand, four hundred seventeen".