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117844141993 = 131899573603
BaseRepresentation
bin110110111000000001…
…1101110011110101001
3102021011202112200021121
41231300003232132221
53412321100020433
6130045320535241
711341200452044
oct1556003563651
9367152480247
10117844141993
1145a82a45096
121aa09921521
13b16066c946
1459bccb9c5b
1530eaaa7c2d
hex1b700ee7a9

117844141993 has 4 divisors (see below), whose sum is σ = 118743715728. Its totient is φ = 116944568260.

The previous prime is 117844141991. The next prime is 117844142021. The reversal of 117844141993 is 399141448711.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 117844141993 - 21 = 117844141991 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 117844141993.

It is not an unprimeable number, because it can be changed into a prime (117844141991) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 449786671 + ... + 449786932.

It is an arithmetic number, because the mean of its divisors is an integer number (29685928932).

Almost surely, 2117844141993 is an apocalyptic number.

It is an amenable number.

117844141993 is a deficient number, since it is larger than the sum of its proper divisors (899573735).

117844141993 is an equidigital number, since it uses as much as digits as its factorization.

117844141993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 899573734.

The product of its digits is 870912, while the sum is 52.

The spelling of 117844141993 in words is "one hundred seventeen billion, eight hundred forty-four million, one hundred forty-one thousand, nine hundred ninety-three".

Divisors: 1 131 899573603 117844141993