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118031614433 is a prime number
BaseRepresentation
bin110110111101100111…
…0111000000111100001
3102021122211022021010022
41231323032320013201
53413212043130213
6130120055043225
711345635111655
oct1557316700741
9367584267108
10118031614433
1146069850997
121aa60670515
13b19045ba95
1459d9b5aa65
15310c28a308
hex1b7b3b81e1

118031614433 has 2 divisors, whose sum is σ = 118031614434. Its totient is φ = 118031614432.

The previous prime is 118031614403. The next prime is 118031614469. The reversal of 118031614433 is 334416130811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97898274769 + 20133339664 = 312887^2 + 141892^2 .

It is a cyclic number.

It is not a de Polignac number, because 118031614433 - 28 = 118031614177 is a prime.

It is a super-2 number, since 2×1180316144332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 118031614393 and 118031614402.

It is not a weakly prime, because it can be changed into another prime (118031614403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59015807216 + 59015807217.

It is an arithmetic number, because the mean of its divisors is an integer number (59015807217).

Almost surely, 2118031614433 is an apocalyptic number.

It is an amenable number.

118031614433 is a deficient number, since it is larger than the sum of its proper divisors (1).

118031614433 is an equidigital number, since it uses as much as digits as its factorization.

118031614433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 35.

The spelling of 118031614433 in words is "one hundred eighteen billion, thirty-one million, six hundred fourteen thousand, four hundred thirty-three".