Base | Representation |
---|---|
bin | 10110000000000001… |
… | …00110101011010001 |
3 | 1010111011002010222001 |
4 | 23000000212223101 |
5 | 143142144142411 |
6 | 5232005314001 |
7 | 565460356564 |
oct | 130000465321 |
9 | 33434063861 |
10 | 11811318481 |
11 | 50111aa436 |
12 | 2357705901 |
13 | 1163041261 |
14 | 8009444db |
15 | 491deedc1 |
hex | 2c0026ad1 |
11811318481 has 2 divisors, whose sum is σ = 11811318482. Its totient is φ = 11811318480.
The previous prime is 11811318469. The next prime is 11811318511. The reversal of 11811318481 is 18481311811.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6006250000 + 5805068481 = 77500^2 + 76191^2 .
It is a cyclic number.
It is not a de Polignac number, because 11811318481 - 213 = 11811310289 is a prime.
It is a super-2 number, since 2×118113184812 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11811318481.
It is not a weakly prime, because it can be changed into another prime (11811318881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5905659240 + 5905659241.
It is an arithmetic number, because the mean of its divisors is an integer number (5905659241).
Almost surely, 211811318481 is an apocalyptic number.
It is an amenable number.
11811318481 is a deficient number, since it is larger than the sum of its proper divisors (1).
11811318481 is an equidigital number, since it uses as much as digits as its factorization.
11811318481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6144, while the sum is 37.
The spelling of 11811318481 in words is "eleven billion, eight hundred eleven million, three hundred eighteen thousand, four hundred eighty-one".
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