1181406433 has 2 divisors, whose sum is σ = 1181406434. Its totient is φ = 1181406432.

The previous prime is 1181406427. The next prime is 1181406481. The reversal of 1181406433 is 3346041811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1181159424 + 247009 = 34368^2 + 497^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1181406433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1181406395 and 1181406404.

It is not a weakly prime, because it can be changed into another prime (1181406493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 590703216 + 590703217.

It is an arithmetic number, because the mean of its divisors is an integer number (590703217).

Almost surely, 2^1181406433 is an apocalyptic number.

It is an amenable number.

1181406433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1181406433 is an equidigital number, since it uses as much as digits as its factorization.

1181406433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 31.

The square root of 1181406433 is about 34371.5934021104. The cubic root of 1181406433 is about 1057.1414714572.

The spelling of 1181406433 in words is "one billion, one hundred eighty-one million, four hundred six thousand, four hundred thirty-three".