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11847321113 = 47924733447
BaseRepresentation
bin10110000100010011…
…11100011000011001
31010120122211021021212
423002021330120121
5143230403233423
65235333112505
7566405365535
oct130211743031
933518737255
1011847321113
11502a55a781
122367788735
13116a6384a4
14805636bc5
15495162578
hex2c227c619

11847321113 has 4 divisors (see below), whose sum is σ = 11872055040. Its totient is φ = 11822587188.

The previous prime is 11847321049. The next prime is 11847321121. The reversal of 11847321113 is 31112374811.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11847321113 - 26 = 11847321049 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11847321113.

It is not an unprimeable number, because it can be changed into a prime (11847341113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12366245 + ... + 12367202.

It is an arithmetic number, because the mean of its divisors is an integer number (2968013760).

Almost surely, 211847321113 is an apocalyptic number.

It is an amenable number.

11847321113 is a deficient number, since it is larger than the sum of its proper divisors (24733927).

11847321113 is an equidigital number, since it uses as much as digits as its factorization.

11847321113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24733926.

The product of its digits is 4032, while the sum is 32.

Adding to 11847321113 its reverse (31112374811), we get a palindrome (42959695924).

The spelling of 11847321113 in words is "eleven billion, eight hundred forty-seven million, three hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 479 24733447 11847321113