Base | Representation |
---|---|
bin | 10110000101011111… |
… | …10100011001110011 |
3 | 1010121100111201000222 |
4 | 23002233310121303 |
5 | 143240423444112 |
6 | 5240330003255 |
7 | 566555650466 |
oct | 130257643163 |
9 | 33540451028 |
10 | 11857249907 |
11 | 5035121398 |
12 | 236ab7652b |
13 | 116c703809 |
14 | 806a9d2dd |
15 | 495e74372 |
hex | 2c2bf4673 |
11857249907 has 2 divisors, whose sum is σ = 11857249908. Its totient is φ = 11857249906.
The previous prime is 11857249841. The next prime is 11857249919. The reversal of 11857249907 is 70994275811.
It is a strong prime.
It is an emirp because it is prime and its reverse (70994275811) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11857249907 - 222 = 11853055603 is a prime.
It is not a weakly prime, because it can be changed into another prime (11857249997) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5928624953 + 5928624954.
It is an arithmetic number, because the mean of its divisors is an integer number (5928624954).
Almost surely, 211857249907 is an apocalyptic number.
11857249907 is a deficient number, since it is larger than the sum of its proper divisors (1).
11857249907 is an equidigital number, since it uses as much as digits as its factorization.
11857249907 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1270080, while the sum is 53.
The spelling of 11857249907 in words is "eleven billion, eight hundred fifty-seven million, two hundred forty-nine thousand, nine hundred seven".
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