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11864433312449 is a prime number
BaseRepresentation
bin1010110010100110011101…
…0101010100001011000001
31120000020011202102211102122
42230221213111110023001
53023341324411444244
641122240113254025
72333114501124254
oct254514725241301
946006152384378
1011864433312449
113864750332a53
1213b74a6864315
13680a714554c3
142d035509b09b
1515894b5181ee
hexaca675542c1

11864433312449 has 2 divisors, whose sum is σ = 11864433312450. Its totient is φ = 11864433312448.

The previous prime is 11864433312397. The next prime is 11864433312461. The reversal of 11864433312449 is 94421333446811.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9103302740224 + 2761130572225 = 3017168^2 + 1661665^2 .

It is a cyclic number.

It is not a de Polignac number, because 11864433312449 - 212 = 11864433308353 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11864433312449.

It is not a weakly prime, because it can be changed into another prime (11864433314449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5932216656224 + 5932216656225.

It is an arithmetic number, because the mean of its divisors is an integer number (5932216656225).

Almost surely, 211864433312449 is an apocalyptic number.

It is an amenable number.

11864433312449 is a deficient number, since it is larger than the sum of its proper divisors (1).

11864433312449 is an equidigital number, since it uses as much as digits as its factorization.

11864433312449 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5971968, while the sum is 53.

The spelling of 11864433312449 in words is "eleven trillion, eight hundred sixty-four billion, four hundred thirty-three million, three hundred twelve thousand, four hundred forty-nine".