Base | Representation |
---|---|
bin | 1010110010101000001101… |
… | …1100110000101011010001 |
3 | 1120000021101122001101010102 |
4 | 2230222003130300223101 |
5 | 3023343311141320012 |
6 | 41122355003542145 |
7 | 2333132256461213 |
oct | 254520334605321 |
9 | 46007348041112 |
10 | 11864905026257 |
11 | 386497262a578 |
12 | 13b75b882a955 |
13 | 680b180b56ba |
14 | 2d039b9ac5b3 |
15 | 158977b452c2 |
hex | aca83730ad1 |
11864905026257 has 2 divisors, whose sum is σ = 11864905026258. Its totient is φ = 11864905026256.
The previous prime is 11864905026239. The next prime is 11864905026323. The reversal of 11864905026257 is 75262050946811.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6252180190096 + 5612724836161 = 2500436^2 + 2369119^2 .
It is a cyclic number.
It is not a de Polignac number, because 11864905026257 - 26 = 11864905026193 is a prime.
It is not a weakly prime, because it can be changed into another prime (11864905028257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5932452513128 + 5932452513129.
It is an arithmetic number, because the mean of its divisors is an integer number (5932452513129).
Almost surely, 211864905026257 is an apocalyptic number.
It is an amenable number.
11864905026257 is a deficient number, since it is larger than the sum of its proper divisors (1).
11864905026257 is an equidigital number, since it uses as much as digits as its factorization.
11864905026257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 56.
The spelling of 11864905026257 in words is "eleven trillion, eight hundred sixty-four billion, nine hundred five million, twenty-six thousand, two hundred fifty-seven".
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